c/c++ linux programming by examples my programming tips and techniques

Some Responses to “Pascal Triangle Challenge” :

1. Here’s mine :-)

   
void piramid(int const c)
{
int r, x;

   /* c: center of pyramid, r: row/height of pyramid */
   for (r = c; r > 0; r--)
   {
   /* int start = r; */
   /* int end = (2 * c - r); */
   /* start: start printing numbers, end: stop printing numbers */

   for (x = 1; x < = (2 * c - r); x++)
{
if (x < r) printf(" ");
else if (x <= c) printf("%d", x - r + 1);
else printf("%d", (2 * c - r) - x + 1);
}
printf("\n");
}
}


   Commented toydi on May 30th, 2007.

2. toydi: Its too bad that the comment here got word count limit, why don’t you post on your blog instead?

   Commented mysurface on May 30th, 2007.

3. the programing techniq is very nice.thanq for helping

   Commented i.siva reddy on August 21st, 2007.

4. That’s not Pascal’s triangle, which contains the coefficients of the
   binomial raised to some given power.

   1
   1 1
   1 2 1
   1 3 3 1
   1 4 6 4 1
   etc.

   And you need only one variable, outside the for look counters, of course.
   Based on the fact that each number is n choose k, with n the row number and k
   the position in the row.

   So it becomes:

   for (unsigned n = 0; n

   Commented dzeta on August 29th, 2007.

5. Truncated code:

   for (unsigned n = 0; n

   Commented dzeta on August 29th, 2007.

6. i want a simple program n its too mch complicated

   Commented nishidh on October 23rd, 2007.

7. check this college level implementation. Hope this is easy to digest.

   #include
   #include
   main()
   {
   int level_count = 0, space_count, i, j;

   printf(”\n Please enter the number of levels for triangle: “);
   scanf(”%d”, &level_count);
   printf(”\n Here goes your pascal triangle \n”);
   space_count = level_count;
   for (i = 0; i < level_count; i++)
   {
   for (j = 0; j < space_count; j++)
   {
   putchar(’ ‘);
   }
   space_count–;
   for (j = 1; j = 1; j–)
   {
   printf(”%d”,j);
   }
   printf(”\n”);
   }
   }

   Commented Subash on July 24th, 2008.

8. that works for applying the spaces, it doesnt answer any questions about the actual calculation of the rows though. you will get a line of 1s decending but how would you go about adding the numbers in the previous row to create the next.

   Commented adam on August 12th, 2008.